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143568037889 is a prime number
BaseRepresentation
bin1000010110110101010…
…0100110100000000001
3111201120111120222120122
42011231110212200001
54323011404203024
6145542041150025
713241515121063
oct2055524464001
9451514528518
10143568037889
1155983461891
12239a878b315
13106ccb61013
146d3d45b733
153b040bcd5e
hex216d526801

143568037889 has 2 divisors, whose sum is σ = 143568037890. Its totient is φ = 143568037888.

The previous prime is 143568037867. The next prime is 143568037891. The reversal of 143568037889 is 988730865341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123745650625 + 19822387264 = 351775^2 + 140792^2 .

It is an emirp because it is prime and its reverse (988730865341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143568037889 is a prime.

It is a super-2 number, since 2×1435680378892 (a number of 23 digits) contains 22 as substring.

Together with 143568037891, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143568037189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71784018944 + 71784018945.

It is an arithmetic number, because the mean of its divisors is an integer number (71784018945).

Almost surely, 2143568037889 is an apocalyptic number.

It is an amenable number.

143568037889 is a deficient number, since it is larger than the sum of its proper divisors (1).

143568037889 is an equidigital number, since it uses as much as digits as its factorization.

143568037889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34836480, while the sum is 62.

The spelling of 143568037889 in words is "one hundred forty-three billion, five hundred sixty-eight million, thirty-seven thousand, eight hundred eighty-nine".