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14365220235181 is a prime number
BaseRepresentation
bin1101000100001010100111…
…0110010110011110101101
31212212022010220020012200121
43101002221312112132231
53340324432340011211
650315142512124541
73011565356211244
oct321025166263655
955768126205617
1014365220235181
11463928a35a9a2
1217400ab236751
13802832b8c09a
143793cd49395b
1519da1426b271
hexd10a9d967ad

14365220235181 has 2 divisors, whose sum is σ = 14365220235182. Its totient is φ = 14365220235180.

The previous prime is 14365220235143. The next prime is 14365220235211. The reversal of 14365220235181 is 18153202256341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9212165874025 + 5153054361156 = 3035155^2 + 2270034^2 .

It is a cyclic number.

It is not a de Polignac number, because 14365220235181 - 29 = 14365220234669 is a prime.

It is a super-2 number, since 2×143652202351812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14365220235781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7182610117590 + 7182610117591.

It is an arithmetic number, because the mean of its divisors is an integer number (7182610117591).

Almost surely, 214365220235181 is an apocalyptic number.

It is an amenable number.

14365220235181 is a deficient number, since it is larger than the sum of its proper divisors (1).

14365220235181 is an equidigital number, since it uses as much as digits as its factorization.

14365220235181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 43.

The spelling of 14365220235181 in words is "fourteen trillion, three hundred sixty-five billion, two hundred twenty million, two hundred thirty-five thousand, one hundred eighty-one".