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14366693813 is a prime number
BaseRepresentation
bin11010110000101001…
…00101100110110101
31101002020110122220212
431120110211212311
5213410333200223
610333332035205
71016006611463
oct153024454665
941066418825
1014366693813
11610269577a
12294b462b05
13147c58b674
149a408b833
15591418278
hex3585259b5

14366693813 has 2 divisors, whose sum is σ = 14366693814. Its totient is φ = 14366693812.

The previous prime is 14366693807. The next prime is 14366693857. The reversal of 14366693813 is 31839666341.

14366693813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12402608689 + 1964085124 = 111367^2 + 44318^2 .

It is a cyclic number.

It is not a de Polignac number, because 14366693813 - 24 = 14366693797 is a prime.

It is a super-2 number, since 2×143666938132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14366693893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7183346906 + 7183346907.

It is an arithmetic number, because the mean of its divisors is an integer number (7183346907).

Almost surely, 214366693813 is an apocalyptic number.

It is an amenable number.

14366693813 is a deficient number, since it is larger than the sum of its proper divisors (1).

14366693813 is an equidigital number, since it uses as much as digits as its factorization.

14366693813 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1679616, while the sum is 50.

The spelling of 14366693813 in words is "fourteen billion, three hundred sixty-six million, six hundred ninety-three thousand, eight hundred thirteen".