Base | Representation |
---|---|
bin | 1101000100100100001110… |
… | …0101101010101111101100 |
3 | 1212212221212222102002002011 |
4 | 3101021003211222233230 |
5 | 3340433022144122200 |
6 | 50322241000011004 |
7 | 3012230620524646 |
oct | 321110345525754 |
9 | 55787788362064 |
10 | 14372094520300 |
11 | 464119774a070 |
12 | 17414a9460a64 |
13 | 80338a119b0a |
14 | 379882447896 |
15 | 19dcb7a015ba |
hex | d124396abec |
14372094520300 has 72 divisors (see below), whose sum is σ = 34168688032752. Its totient is φ = 5203785984000.
The previous prime is 14372094520261. The next prime is 14372094520321. The reversal of 14372094520300 is 302549027341.
14372094520300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×143720945203002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27781341 + ... + 28293940.
It is an arithmetic number, because the mean of its divisors is an integer number (474565111566).
Almost surely, 214372094520300 is an apocalyptic number.
14372094520300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14372094520300 is an abundant number, since it is smaller than the sum of its proper divisors (19796593512452).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14372094520300 is a wasteful number, since it uses less digits than its factorization.
14372094520300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56075539 (or 56075532 counting only the distinct ones).
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 14372094520300 in words is "fourteen trillion, three hundred seventy-two billion, ninety-four million, five hundred twenty thousand, three hundred".
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