14394433 has 2 divisors, whose sum is σ = 14394434. Its totient is φ = 14394432.

The previous prime is 14394409. The next prime is 14394437. The reversal of 14394433 is 33449341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8862529 + 5531904 = 2977^2 + 2352^2 .

It is a cyclic number.

It is not a de Polignac number, because 14394433 - 2¹³ = 14386241 is a prime.

It is equal to p₉₃₄₀₉₆ and since 14394433 and 934096 have the same sum of digits, it is a Honaker prime.

It is a nialpdrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 14394395 and 14394404.

It is not a weakly prime, because it can be changed into another prime (14394437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7197216 + 7197217.

It is an arithmetic number, because the mean of its divisors is an integer number (7197217).

Almost surely, 2^14394433 is an apocalyptic number.

It is an amenable number.

14394433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14394433 is an equidigital number, since it uses as much as digits as its factorization.

14394433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 31.

The square root of 14394433 is about 3793.9996046389. Note that the first 3 decimals coincide. The cubic root of 14394433 is about 243.2567242833.

The spelling of 14394433 in words is "fourteen million, three hundred ninety-four thousand, four hundred thirty-three".