Base | Representation |
---|---|
bin | 1101000110001100010001… |
… | …0101000001011000010011 |
3 | 1212222121222110001212222221 |
4 | 3101203010111001120103 |
5 | 3341412222200034303 |
6 | 50343140234241511 |
7 | 3014240011211245 |
oct | 321430425013023 |
9 | 55877873055887 |
10 | 14400024221203 |
11 | 465201a2a0805 |
12 | 17469a2b86297 |
13 | 805bbb5c2b5a |
14 | 37ad71938095 |
15 | 19e89e9cd4bd |
hex | d18c4541613 |
14400024221203 has 2 divisors, whose sum is σ = 14400024221204. Its totient is φ = 14400024221202.
The previous prime is 14400024221171. The next prime is 14400024221221. The reversal of 14400024221203 is 30212242000441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14400024221203 - 25 = 14400024221171 is a prime.
It is not a weakly prime, because it can be changed into another prime (14400024221003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200012110601 + 7200012110602.
It is an arithmetic number, because the mean of its divisors is an integer number (7200012110602).
Almost surely, 214400024221203 is an apocalyptic number.
14400024221203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14400024221203 is an equidigital number, since it uses as much as digits as its factorization.
14400024221203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 14400024221203 its reverse (30212242000441), we get a palindrome (44612266221644).
The spelling of 14400024221203 in words is "fourteen trillion, four hundred billion, twenty-four million, two hundred twenty-one thousand, two hundred three".
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