Base | Representation |
---|---|
bin | 1000011000011101000… |
… | …0010010010111000001 |
3 | 111202200211021011101201 |
4 | 2012013100102113001 |
5 | 4324404244130213 |
6 | 150053142301201 |
7 | 13255350163603 |
oct | 2060720222701 |
9 | 452624234351 |
10 | 144003114433 |
11 | 56087005282 |
12 | 23aaa427801 |
13 | 1076c034169 |
14 | 6d81153173 |
15 | 3b2c3ae6dd |
hex | 21874125c1 |
144003114433 has 2 divisors, whose sum is σ = 144003114434. Its totient is φ = 144003114432.
The previous prime is 144003114401. The next prime is 144003114503. The reversal of 144003114433 is 334411300441.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116846381584 + 27156732849 = 341828^2 + 164793^2 .
It is a cyclic number.
It is not a de Polignac number, because 144003114433 - 25 = 144003114401 is a prime.
It is a super-2 number, since 2×1440031144332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (144003184433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72001557216 + 72001557217.
It is an arithmetic number, because the mean of its divisors is an integer number (72001557217).
Almost surely, 2144003114433 is an apocalyptic number.
It is an amenable number.
144003114433 is a deficient number, since it is larger than the sum of its proper divisors (1).
144003114433 is an equidigital number, since it uses as much as digits as its factorization.
144003114433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 144003114433 its reverse (334411300441), we get a palindrome (478414414874).
The spelling of 144003114433 in words is "one hundred forty-four billion, three million, one hundred fourteen thousand, four hundred thirty-three".
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