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144003114433 is a prime number
BaseRepresentation
bin1000011000011101000…
…0010010010111000001
3111202200211021011101201
42012013100102113001
54324404244130213
6150053142301201
713255350163603
oct2060720222701
9452624234351
10144003114433
1156087005282
1223aaa427801
131076c034169
146d81153173
153b2c3ae6dd
hex21874125c1

144003114433 has 2 divisors, whose sum is σ = 144003114434. Its totient is φ = 144003114432.

The previous prime is 144003114401. The next prime is 144003114503. The reversal of 144003114433 is 334411300441.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116846381584 + 27156732849 = 341828^2 + 164793^2 .

It is a cyclic number.

It is not a de Polignac number, because 144003114433 - 25 = 144003114401 is a prime.

It is a super-2 number, since 2×1440031144332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144003184433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72001557216 + 72001557217.

It is an arithmetic number, because the mean of its divisors is an integer number (72001557217).

Almost surely, 2144003114433 is an apocalyptic number.

It is an amenable number.

144003114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144003114433 is an equidigital number, since it uses as much as digits as its factorization.

144003114433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 144003114433 its reverse (334411300441), we get a palindrome (478414414874).

The spelling of 144003114433 in words is "one hundred forty-four billion, three million, one hundred fourteen thousand, four hundred thirty-three".