1440054101117 has 2 divisors, whose sum is σ = 1440054101118. Its totient is φ = 1440054101116.

The previous prime is 1440054101093. The next prime is 1440054101173. The reversal of 1440054101117 is 7111014500441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 874325982916 + 565728118201 = 935054^2 + 752149^2 .

It is a cyclic number.

It is not a de Polignac number, because 1440054101117 - 2⁶ = 1440054101053 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1440054101117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1440054101197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720027050558 + 720027050559.

It is an arithmetic number, because the mean of its divisors is an integer number (720027050559).

Almost surely, 2^{1440054101117} is an apocalyptic number.

It is an amenable number.

1440054101117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440054101117 is an equidigital number, since it uses as much as digits as its factorization.

1440054101117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2240, while the sum is 29.

Adding to 1440054101117 its reverse (7111014500441), we get a palindrome (8551068601558).

The spelling of 1440054101117 in words is "one trillion, four hundred forty billion, fifty-four million, one hundred one thousand, one hundred seventeen".