Base | Representation |
---|---|
bin | 1000011000011110111… |
… | …1010010001001101111 |
3 | 111202201101112222122101 |
4 | 2012013233102021233 |
5 | 4324413334140142 |
6 | 150054032355531 |
7 | 13255506225463 |
oct | 2060757221157 |
9 | 452641488571 |
10 | 144011240047 |
11 | 56090655164 |
12 | 23ab10a5ba7 |
13 | 1077091a80c |
14 | 6d8226a4a3 |
15 | 3b2ce670b7 |
hex | 2187bd226f |
144011240047 has 2 divisors, whose sum is σ = 144011240048. Its totient is φ = 144011240046.
The previous prime is 144011240011. The next prime is 144011240057. The reversal of 144011240047 is 740042110441.
It is a strong prime.
It is an emirp because it is prime and its reverse (740042110441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 144011240047 - 211 = 144011237999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 144011239997 and 144011240024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144011240057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72005620023 + 72005620024.
It is an arithmetic number, because the mean of its divisors is an integer number (72005620024).
Almost surely, 2144011240047 is an apocalyptic number.
144011240047 is a deficient number, since it is larger than the sum of its proper divisors (1).
144011240047 is an equidigital number, since it uses as much as digits as its factorization.
144011240047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3584, while the sum is 28.
Adding to 144011240047 its reverse (740042110441), we get a palindrome (884053350488).
The spelling of 144011240047 in words is "one hundred forty-four billion, eleven million, two hundred forty thousand, forty-seven".
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