14401240331 has 2 divisors, whose sum is σ = 14401240332. Its totient is φ = 14401240330.

The previous prime is 14401240303. The next prime is 14401240333. The reversal of 14401240331 is 13304210441.

It is a strong prime.

It is an emirp because it is prime and its reverse (13304210441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14401240331 - 2¹⁸ = 14400978187 is a prime.

It is a super-2 number, since 2×14401240331² (a number of 21 digits) contains 22 as substring.

Together with 14401240333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14401240297 and 14401240306.

It is not a weakly prime, because it can be changed into another prime (14401240333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200620165 + 7200620166.

It is an arithmetic number, because the mean of its divisors is an integer number (7200620166).

Almost surely, 2^14401240331 is an apocalyptic number.

14401240331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401240331 is an equidigital number, since it uses as much as digits as its factorization.

14401240331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14401240331 its reverse (13304210441), we get a palindrome (27705450772).

The spelling of 14401240331 in words is "fourteen billion, four hundred one million, two hundred forty thousand, three hundred thirty-one".