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14401301293 is a prime number
BaseRepresentation
bin11010110100110001…
…00110101100101101
31101011122120220110101
431122120212230231
5213443213120133
610341005511101
71016610020101
oct153230465455
941148526411
1014401301293
1161201828a5
12295ab72491
1314867b7872
149a88d9901
155944a237d
hex35a626b2d

14401301293 has 2 divisors, whose sum is σ = 14401301294. Its totient is φ = 14401301292.

The previous prime is 14401301251. The next prime is 14401301303. The reversal of 14401301293 is 39210310441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14160524004 + 240777289 = 118998^2 + 15517^2 .

It is an emirp because it is prime and its reverse (39210310441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14401301293 is a prime.

It is a super-4 number, since 4×144013012934 (a number of 42 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14401301393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200650646 + 7200650647.

It is an arithmetic number, because the mean of its divisors is an integer number (7200650647).

Almost surely, 214401301293 is an apocalyptic number.

It is an amenable number.

14401301293 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401301293 is an equidigital number, since it uses as much as digits as its factorization.

14401301293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 14401301293 in words is "fourteen billion, four hundred one million, three hundred one thousand, two hundred ninety-three".