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1440202121130 = 23548006737371
BaseRepresentation
bin10100111101010010101…
…111000101111110101010
312002200102011101011001010
4110331102233011332222
5142044013220334010
63021341505404350
7206023360021203
oct24752257057652
95080364334033
101440202121130
11505871607993
121b31549396b6
13a5a6c807026
144d9c598c5aa
15276e276e620
hex14f52bc5faa

1440202121130 has 16 divisors (see below), whose sum is σ = 3456485090784. Its totient is φ = 384053898960.

The previous prime is 1440202121129. The next prime is 1440202121153. The reversal of 1440202121130 is 311212020441.

It is a junction number, because it is equal to n+sod(n) for n = 1440202121097 and 1440202121106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24003368656 + ... + 24003368715.

It is an arithmetic number, because the mean of its divisors is an integer number (216030318174).

Almost surely, 21440202121130 is an apocalyptic number.

1440202121130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1440202121130 is an abundant number, since it is smaller than the sum of its proper divisors (2016282969654).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1440202121130 is a wasteful number, since it uses less digits than its factorization.

1440202121130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48006737381.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1440202121130 its reverse (311212020441), we get a palindrome (1751414141571).

The spelling of 1440202121130 in words is "one trillion, four hundred forty billion, two hundred two million, one hundred twenty-one thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 48006737371 96013474742 144020212113 240033686855 288040424226 480067373710 720101060565 1440202121130