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144020451241 is a prime number
BaseRepresentation
bin1000011000100001001…
…0011010111110101001
3111202202000212222000201
42012020102122332221
54324423213414431
6150055002032201
713255650431332
oct2061022327651
9452660788021
10144020451241
1156095876717
1223ab41a8661
13107727c4324
146d83587289
153b2db86461
hex218849afa9

144020451241 has 2 divisors, whose sum is σ = 144020451242. Its totient is φ = 144020451240.

The previous prime is 144020451221. The next prime is 144020451299. The reversal of 144020451241 is 142154020441.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128095273216 + 15925178025 = 357904^2 + 126195^2 .

It is a cyclic number.

It is not a de Polignac number, because 144020451241 - 25 = 144020451209 is a prime.

It is a super-2 number, since 2×1440204512412 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144020451221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72010225620 + 72010225621.

It is an arithmetic number, because the mean of its divisors is an integer number (72010225621).

Almost surely, 2144020451241 is an apocalyptic number.

It is an amenable number.

144020451241 is a deficient number, since it is larger than the sum of its proper divisors (1).

144020451241 is an equidigital number, since it uses as much as digits as its factorization.

144020451241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5120, while the sum is 28.

Adding to 144020451241 its reverse (142154020441), we get a palindrome (286174471682).

The spelling of 144020451241 in words is "one hundred forty-four billion, twenty million, four hundred fifty-one thousand, two hundred forty-one".