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144023032504523 is a prime number
BaseRepresentation
bin100000101111110011111001…
…101100010010000011001011
3200212221110121202122200221102
4200233303321230102003023
5122334133132310121043
61230151133455332015
742223215002251154
oct4057637154220313
9625843552580842
10144023032504523
11419879091a3417
12141a076622100b
136249410239223
14277ca7557a92b
15119b5825776b8
hex82fcf9b120cb

144023032504523 has 2 divisors, whose sum is σ = 144023032504524. Its totient is φ = 144023032504522.

The previous prime is 144023032504513. The next prime is 144023032504531. The reversal of 144023032504523 is 325405230320441.

144023032504523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 144023032504523 - 230 = 144021958762699 is a prime.

It is not a weakly prime, because it can be changed into another prime (144023032504513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72011516252261 + 72011516252262.

It is an arithmetic number, because the mean of its divisors is an integer number (72011516252262).

Almost surely, 2144023032504523 is an apocalyptic number.

144023032504523 is a deficient number, since it is larger than the sum of its proper divisors (1).

144023032504523 is an equidigital number, since it uses as much as digits as its factorization.

144023032504523 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 144023032504523 its reverse (325405230320441), we get a palindrome (469428262824964).

The spelling of 144023032504523 in words is "one hundred forty-four trillion, twenty-three billion, thirty-two million, five hundred four thousand, five hundred twenty-three".