Base | Representation |
---|---|
bin | 11010110100111110… |
… | …10000100010100110 |
3 | 1101011202212112010012 |
4 | 31122133100202212 |
5 | 213444134424132 |
6 | 10341111130222 |
7 | 1016630603264 |
oct | 153237204246 |
9 | 41152775105 |
10 | 14403045542 |
11 | 6121164326 |
12 | 295b673972 |
13 | 1486c78772 |
14 | 9a8c31434 |
15 | 5946e90b2 |
hex | 35a7d08a6 |
14403045542 has 4 divisors (see below), whose sum is σ = 21604568316. Its totient is φ = 7201522770.
The previous prime is 14403045539. The next prime is 14403045577. The reversal of 14403045542 is 24554030441.
14403045542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24554030441 = 106669 ⋅230189.
It is a junction number, because it is equal to n+sod(n) for n = 14403045499 and 14403045508.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3600761384 + ... + 3600761387.
It is an arithmetic number, because the mean of its divisors is an integer number (5401142079).
Almost surely, 214403045542 is an apocalyptic number.
14403045542 is a deficient number, since it is larger than the sum of its proper divisors (7201522774).
14403045542 is an equidigital number, since it uses as much as digits as its factorization.
14403045542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7201522773.
The product of its (nonzero) digits is 38400, while the sum is 32.
Adding to 14403045542 its reverse (24554030441), we get a palindrome (38957075983).
The spelling of 14403045542 in words is "fourteen billion, four hundred three million, forty-five thousand, five hundred forty-two".
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