Base | Representation |
---|---|
bin | 1000011000100100001… |
… | …0110001000001010000 |
3 | 111202202220201211101011 |
4 | 2012021002301001100 |
5 | 4324434434440212 |
6 | 150100133420304 |
7 | 13256163233401 |
oct | 2061102610120 |
9 | 452686654334 |
10 | 144033124432 |
11 | 560a1a4222a |
12 | 23ab849a694 |
13 | 10775310862 |
14 | 6d851259a8 |
15 | 3b2ed3b4a7 |
hex | 21890b1050 |
144033124432 has 10 divisors (see below), whose sum is σ = 279064178618. Its totient is φ = 72016562208.
The previous prime is 144033124409. The next prime is 144033124441. The reversal of 144033124432 is 234421330441.
It can be written as a sum of positive squares in only one way, i.e., 127989355536 + 16043768896 = 357756^2 + 126664^2 .
It is a junction number, because it is equal to n+sod(n) for n = 144033124394 and 144033124403.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4501035123 + ... + 4501035154.
Almost surely, 2144033124432 is an apocalyptic number.
It is an amenable number.
144033124432 is a deficient number, since it is larger than the sum of its proper divisors (135031054186).
144033124432 is an equidigital number, since it uses as much as digits as its factorization.
144033124432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9002070285 (or 9002070279 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 144033124432 its reverse (234421330441), we get a palindrome (378454454873).
The spelling of 144033124432 in words is "one hundred forty-four billion, thirty-three million, one hundred twenty-four thousand, four hundred thirty-two".
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