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1440420131 is a prime number
BaseRepresentation
bin101010111011011…
…0001000100100011
310201101101220221202
41111312301010203
510422221421011
6354533111415
750460240413
oct12566610443
93641356852
101440420131
1167a096a67
1234248856b
1319c561607
14d9434643
15866cb23b
hex55db1123

1440420131 has 2 divisors, whose sum is σ = 1440420132. Its totient is φ = 1440420130.

The previous prime is 1440420089. The next prime is 1440420173. The reversal of 1440420131 is 1310240441.

It is a balanced prime because it is at equal distance from previous prime (1440420089) and next prime (1440420173).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1440420131 is a prime.

It is a super-2 number, since 2×14404201312 = 4149620307580114322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1440422131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720210065 + 720210066.

It is an arithmetic number, because the mean of its divisors is an integer number (720210066).

Almost surely, 21440420131 is an apocalyptic number.

1440420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440420131 is an equidigital number, since it uses as much as digits as its factorization.

1440420131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 1440420131 is about 37952.8672302897. The cubic root of 1440420131 is about 1129.3530457585.

Adding to 1440420131 its reverse (1310240441), we get a palindrome (2750660572).

The spelling of 1440420131 in words is "one billion, four hundred forty million, four hundred twenty thousand, one hundred thirty-one".