Base | Representation |
---|---|
bin | 1101000110100000110010… |
… | …0100111101000010000111 |
3 | 1220000011012020122201120121 |
4 | 3101220030210331002013 |
5 | 3342010012004341201 |
6 | 50345450522442411 |
7 | 3014523331626163 |
oct | 321501444750207 |
9 | 56004166581517 |
10 | 14405531324551 |
11 | 4654395976a94 |
12 | 1747a7b363407 |
13 | 806588522aa3 |
14 | 37b3350bdca3 |
15 | 19eac32029a1 |
hex | d1a0c93d087 |
14405531324551 has 2 divisors, whose sum is σ = 14405531324552. Its totient is φ = 14405531324550.
The previous prime is 14405531324519. The next prime is 14405531324579. The reversal of 14405531324551 is 15542313550441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14405531324551 - 25 = 14405531324519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14405531324498 and 14405531324507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14405531324581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7202765662275 + 7202765662276.
It is an arithmetic number, because the mean of its divisors is an integer number (7202765662276).
Almost surely, 214405531324551 is an apocalyptic number.
14405531324551 is a deficient number, since it is larger than the sum of its proper divisors (1).
14405531324551 is an equidigital number, since it uses as much as digits as its factorization.
14405531324551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 14405531324551 its reverse (15542313550441), we get a palindrome (29947844874992).
The spelling of 14405531324551 in words is "fourteen trillion, four hundred five billion, five hundred thirty-one million, three hundred twenty-four thousand, five hundred fifty-one".
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