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14405694471943 is a prime number
BaseRepresentation
bin1101000110100001011001…
…0011010011111100000111
31220000011121121122110201121
43101220112103103330013
53342010330241100233
650345515031334411
73014530352434435
oct321502623237407
956004547573647
1014405694471943
114654469a79045
121747b05b21407
138065b3275cc8
1437b34ca2bd55
1519ead26cc92d
hexd1a164d3f07

14405694471943 has 2 divisors, whose sum is σ = 14405694471944. Its totient is φ = 14405694471942.

The previous prime is 14405694471841. The next prime is 14405694471983. The reversal of 14405694471943 is 34917449650441.

14405694471943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14405694471943 - 221 = 14405692374791 is a prime.

It is a super-2 number, since 2×144056944719432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14405694471983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7202847235971 + 7202847235972.

It is an arithmetic number, because the mean of its divisors is an integer number (7202847235972).

Almost surely, 214405694471943 is an apocalyptic number.

14405694471943 is a deficient number, since it is larger than the sum of its proper divisors (1).

14405694471943 is an equidigital number, since it uses as much as digits as its factorization.

14405694471943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52254720, while the sum is 61.

The spelling of 14405694471943 in words is "fourteen trillion, four hundred five billion, six hundred ninety-four million, four hundred seventy-one thousand, nine hundred forty-three".