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144100403031413 is a prime number
BaseRepresentation
bin100000110000111011111101…
…010101011010110101110101
3200220012212022211221200221102
4200300323331111122311311
5122341420111134001123
61230250451122255445
742231624215006333
oct4060737525326565
9626185284850842
10144100403031413
1141a07701904424
12141b37594b7585
1362537c067bb9a
1427826d5000b53
15119d5aec93028
hex830efd55ad75

144100403031413 has 2 divisors, whose sum is σ = 144100403031414. Its totient is φ = 144100403031412.

The previous prime is 144100403031349. The next prime is 144100403031421. The reversal of 144100403031413 is 314130304001441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85217601270244 + 58882801761169 = 9231338^2 + 7673513^2 .

It is an emirp because it is prime and its reverse (314130304001441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144100403031413 - 26 = 144100403031349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144100403033413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72050201515706 + 72050201515707.

It is an arithmetic number, because the mean of its divisors is an integer number (72050201515707).

Almost surely, 2144100403031413 is an apocalyptic number.

It is an amenable number.

144100403031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

144100403031413 is an equidigital number, since it uses as much as digits as its factorization.

144100403031413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 144100403031413 its reverse (314130304001441), we get a palindrome (458230707032854).

The spelling of 144100403031413 in words is "one hundred forty-four trillion, one hundred billion, four hundred three million, thirty-one thousand, four hundred thirteen".