Base | Representation |
---|---|
bin | 1101000110110101001101… |
… | …0011110001110000010111 |
3 | 1220000200100021100020121021 |
4 | 3101231103103301300113 |
5 | 3342102223310042133 |
6 | 50352154501302011 |
7 | 3015106223101246 |
oct | 321552323616027 |
9 | 56020307306537 |
10 | 14411012971543 |
11 | 4656749145561 |
12 | 1748b4b104907 |
13 | 806c500abba6 |
14 | 37b6d511a95d |
15 | 19ece459952d |
hex | d1b534f1c17 |
14411012971543 has 2 divisors, whose sum is σ = 14411012971544. Its totient is φ = 14411012971542.
The previous prime is 14411012971489. The next prime is 14411012971583. The reversal of 14411012971543 is 34517921011441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14411012971543 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14411012971543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14411012971583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205506485771 + 7205506485772.
It is an arithmetic number, because the mean of its divisors is an integer number (7205506485772).
Almost surely, 214411012971543 is an apocalyptic number.
14411012971543 is a deficient number, since it is larger than the sum of its proper divisors (1).
14411012971543 is an equidigital number, since it uses as much as digits as its factorization.
14411012971543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 43.
Adding to 14411012971543 its reverse (34517921011441), we get a palindrome (48928933982984).
The spelling of 14411012971543 in words is "fourteen trillion, four hundred eleven billion, twelve million, nine hundred seventy-one thousand, five hundred forty-three".
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