Base | Representation |
---|---|
bin | 1101000110110101101100… |
… | …0011111000001010010001 |
3 | 1220000200200100001110012021 |
4 | 3101231123003320022101 |
5 | 3342103010103134301 |
6 | 50352215424531441 |
7 | 3015112362356623 |
oct | 321553303701221 |
9 | 56020610043167 |
10 | 14411143021201 |
11 | 46568055a0813 |
12 | 1748b86780b81 |
13 | 806c71014154 |
14 | 37b7084d0c13 |
15 | 19ed00bd78a1 |
hex | d1b5b0f8291 |
14411143021201 has 2 divisors, whose sum is σ = 14411143021202. Its totient is φ = 14411143021200.
The previous prime is 14411143021183. The next prime is 14411143021211. The reversal of 14411143021201 is 10212034111441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11101217758801 + 3309925262400 = 3331849^2 + 1819320^2 .
It is a cyclic number.
It is not a de Polignac number, because 14411143021201 - 217 = 14411142890129 is a prime.
It is not a weakly prime, because it can be changed into another prime (14411143021211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205571510600 + 7205571510601.
It is an arithmetic number, because the mean of its divisors is an integer number (7205571510601).
Almost surely, 214411143021201 is an apocalyptic number.
It is an amenable number.
14411143021201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14411143021201 is an equidigital number, since it uses as much as digits as its factorization.
14411143021201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 14411143021201 its reverse (10212034111441), we get a palindrome (24623177132642).
The spelling of 14411143021201 in words is "fourteen trillion, four hundred eleven billion, one hundred forty-three million, twenty-one thousand, two hundred one".
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