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14411402041 is a prime number
BaseRepresentation
bin11010110101111110…
…01000101100111001
31101012100121002002011
431122333020230321
5214003304331131
610342010205521
71020061616251
oct153277105471
941170532064
1014411402041
116125951723
1229624238a1
13148891323a
149a9da8961
155952ea0b1
hex35afc8b39

14411402041 has 2 divisors, whose sum is σ = 14411402042. Its totient is φ = 14411402040.

The previous prime is 14411402029. The next prime is 14411402053. The reversal of 14411402041 is 14020411441.

It is a balanced prime because it is at equal distance from previous prime (14411402029) and next prime (14411402053).

It can be written as a sum of positive squares in only one way, i.e., 14106550441 + 304851600 = 118771^2 + 17460^2 .

It is an emirp because it is prime and its reverse (14020411441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14411402041 - 211 = 14411399993 is a prime.

It is not a weakly prime, because it can be changed into another prime (14411402011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205701020 + 7205701021.

It is an arithmetic number, because the mean of its divisors is an integer number (7205701021).

Almost surely, 214411402041 is an apocalyptic number.

It is an amenable number.

14411402041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14411402041 is an equidigital number, since it uses as much as digits as its factorization.

14411402041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 512, while the sum is 22.

Adding to 14411402041 its reverse (14020411441), we get a palindrome (28431813482).

The spelling of 14411402041 in words is "fourteen billion, four hundred eleven million, four hundred two thousand, forty-one".