Base | Representation |
---|---|
bin | 100000110001001000110011… |
… | …111001010110111110100011 |
3 | 200220021011221121122012220001 |
4 | 200301020303321112332203 |
5 | 122342131342022334243 |
6 | 1230301052342400431 |
7 | 42232623206400421 |
oct | 4061106371267643 |
9 | 626234847565801 |
10 | 144114203324323 |
11 | 41a125437aa781 |
12 | 141b636b130117 |
13 | 6254bac7a6b8b |
14 | 2783243b70111 |
15 | 119db1b5c8a4d |
hex | 831233e56fa3 |
144114203324323 has 2 divisors, whose sum is σ = 144114203324324. Its totient is φ = 144114203324322.
The previous prime is 144114203324321. The next prime is 144114203324347. The reversal of 144114203324323 is 323423302411441.
144114203324323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144114203324323 - 21 = 144114203324321 is a prime.
Together with 144114203324321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (144114203324321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72057101662161 + 72057101662162.
It is an arithmetic number, because the mean of its divisors is an integer number (72057101662162).
Almost surely, 2144114203324323 is an apocalyptic number.
144114203324323 is a deficient number, since it is larger than the sum of its proper divisors (1).
144114203324323 is an equidigital number, since it uses as much as digits as its factorization.
144114203324323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 37.
Adding to 144114203324323 its reverse (323423302411441), we get a palindrome (467537505735764).
The spelling of 144114203324323 in words is "one hundred forty-four trillion, one hundred fourteen billion, two hundred three million, three hundred twenty-four thousand, three hundred twenty-three".
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