14412125153537 has 2 divisors, whose sum is σ = 14412125153538. Its totient is φ = 14412125153536.

The previous prime is 14412125153441. The next prime is 14412125153539. The reversal of 14412125153537 is 73535152121441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13945623859456 + 466501294081 = 3734384^2 + 683009^2 .

It is a cyclic number.

It is not a de Polignac number, because 14412125153537 - 2¹⁶ = 14412125088001 is a prime.

It is a super-2 number, since 2×14412125153537² (a number of 27 digits) contains 22 as substring.

Together with 14412125153539, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14412125153539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206062576768 + 7206062576769.

It is an arithmetic number, because the mean of its divisors is an integer number (7206062576769).

Almost surely, 2^{14412125153537} is an apocalyptic number.

It is an amenable number.

14412125153537 is a deficient number, since it is larger than the sum of its proper divisors (1).

14412125153537 is an equidigital number, since it uses as much as digits as its factorization.

14412125153537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 504000, while the sum is 44.

Adding to 14412125153537 its reverse (73535152121441), we get a palindrome (87947277274978).

The spelling of 14412125153537 in words is "fourteen trillion, four hundred twelve billion, one hundred twenty-five million, one hundred fifty-three thousand, five hundred thirty-seven".