Base | Representation |
---|---|
bin | 1000011000111001101… |
… | …0011011011001110111 |
3 | 111210000012020211020202 |
4 | 2012032122123121313 |
5 | 4330131020312211 |
6 | 150113112351115 |
7 | 13261336046501 |
oct | 2061632333167 |
9 | 453005224222 |
10 | 144123213431 |
11 | 5613888444a |
12 | 23b226a549b |
13 | 1078ab94162 |
14 | 6d93096d71 |
15 | 3b37bd453b |
hex | 218e69b677 |
144123213431 has 2 divisors, whose sum is σ = 144123213432. Its totient is φ = 144123213430.
The previous prime is 144123213413. The next prime is 144123213439. The reversal of 144123213431 is 134312321441.
Together with previous prime (144123213413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144123213431 is a prime.
It is a super-2 number, since 2×1441232134312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 144123213394 and 144123213403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144123213439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72061606715 + 72061606716.
It is an arithmetic number, because the mean of its divisors is an integer number (72061606716).
Almost surely, 2144123213431 is an apocalyptic number.
144123213431 is a deficient number, since it is larger than the sum of its proper divisors (1).
144123213431 is an equidigital number, since it uses as much as digits as its factorization.
144123213431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 144123213431 its reverse (134312321441), we get a palindrome (278435534872).
The spelling of 144123213431 in words is "one hundred forty-four billion, one hundred twenty-three million, two hundred thirteen thousand, four hundred thirty-one".
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