Base | Representation |
---|---|
bin | 100000110001011000101111… |
… | …001100000111000110000111 |
3 | 200220022211002101222212220211 |
4 | 200301120233030013012013 |
5 | 122342421402340114421 |
6 | 1230313001310140251 |
7 | 42234100036546252 |
oct | 4061305714070607 |
9 | 626284071885824 |
10 | 144131304223111 |
11 | 41a19819814087 |
12 | 141b97421b1687 |
13 | 62566a6666bba |
14 | 2783dc6dd6099 |
15 | 119e2bca819e1 |
hex | 83162f307187 |
144131304223111 has 2 divisors, whose sum is σ = 144131304223112. Its totient is φ = 144131304223110.
The previous prime is 144131304223033. The next prime is 144131304223117. The reversal of 144131304223111 is 111322403131441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144131304223111 - 29 = 144131304222599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144131304223117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72065652111555 + 72065652111556.
It is an arithmetic number, because the mean of its divisors is an integer number (72065652111556).
Almost surely, 2144131304223111 is an apocalyptic number.
144131304223111 is a deficient number, since it is larger than the sum of its proper divisors (1).
144131304223111 is an equidigital number, since it uses as much as digits as its factorization.
144131304223111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 144131304223111 its reverse (111322403131441), we get a palindrome (255453707354552).
The spelling of 144131304223111 in words is "one hundred forty-four trillion, one hundred thirty-one billion, three hundred four million, two hundred twenty-three thousand, one hundred eleven".
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