Base | Representation |
---|---|
bin | 1101000111000000100010… |
… | …0101100100100100001001 |
3 | 1220000222012020011100122212 |
4 | 3101300020211210210021 |
5 | 3342124440400442301 |
6 | 50353420343554505 |
7 | 3015244463054525 |
oct | 321601045444411 |
9 | 56028166140585 |
10 | 14414054312201 |
11 | 4657a69981835 |
12 | 174965975ba35 |
13 | 80731620924b |
14 | 37b903004d85 |
15 | 19ee215a74bb |
hex | d1c08964909 |
14414054312201 has 2 divisors, whose sum is σ = 14414054312202. Its totient is φ = 14414054312200.
The previous prime is 14414054312159. The next prime is 14414054312213. The reversal of 14414054312201 is 10221345041441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8644335015625 + 5769719296576 = 2940125^2 + 2402024^2 .
It is a cyclic number.
It is not a de Polignac number, because 14414054312201 - 222 = 14414050117897 is a prime.
It is not a weakly prime, because it can be changed into another prime (14414054318201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7207027156100 + 7207027156101.
It is an arithmetic number, because the mean of its divisors is an integer number (7207027156101).
Almost surely, 214414054312201 is an apocalyptic number.
It is an amenable number.
14414054312201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14414054312201 is an equidigital number, since it uses as much as digits as its factorization.
14414054312201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 14414054312201 its reverse (10221345041441), we get a palindrome (24635399353642).
The spelling of 14414054312201 in words is "fourteen trillion, four hundred fourteen billion, fifty-four million, three hundred twelve thousand, two hundred one".
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