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14414431300 = 2252144144313
BaseRepresentation
bin11010110110010101…
…01100010001000100
31101012120021222102221
431123022230101010
5214010043300200
610342155142124
71020126434023
oct153312542104
941176258387
1014414431300
116127630645
122963444944
131489433cb9
149aa5568ba
155956e791a
hex35b2ac444

14414431300 has 18 divisors (see below), whose sum is σ = 31279316138. Its totient is φ = 5765772480.

The previous prime is 14414431279. The next prime is 14414431309. The reversal of 14414431300 is 313441441.

It can be written as a sum of positive squares in 3 ways, for example, as 701084484 + 13713346816 = 26478^2 + 117104^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (14414431309) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 72072057 + ... + 72072256.

Almost surely, 214414431300 is an apocalyptic number.

14414431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14414431300 is an abundant number, since it is smaller than the sum of its proper divisors (16864884838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14414431300 is a wasteful number, since it uses less digits than its factorization.

14414431300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144144327 (or 144144320 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14414431300 its reverse (313441441), we get a palindrome (14727872741).

The spelling of 14414431300 in words is "fourteen billion, four hundred fourteen million, four hundred thirty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 144144313 288288626 576577252 720721565 1441443130 2882886260 3603607825 7207215650 14414431300