Base | Representation |
---|---|
bin | 100000110001101100111101… |
… | …100111100110100101110111 |
3 | 200220101220010220012221200011 |
4 | 200301230331213212211313 |
5 | 122343300341403210021 |
6 | 1230330552251201051 |
7 | 42235466150424535 |
oct | 4061547547464567 |
9 | 626356126187604 |
10 | 144153021147511 |
11 | 41a27a53415892 |
12 | 142019a3146187 |
13 | 625875796561c |
14 | 278508732b155 |
15 | 119eb3e3e5de1 |
hex | 831b3d9e6977 |
144153021147511 has 2 divisors, whose sum is σ = 144153021147512. Its totient is φ = 144153021147510.
The previous prime is 144153021147493. The next prime is 144153021147523. The reversal of 144153021147511 is 115741120351441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144153021147511 - 25 = 144153021147479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144153021141511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72076510573755 + 72076510573756.
It is an arithmetic number, because the mean of its divisors is an integer number (72076510573756).
Almost surely, 2144153021147511 is an apocalyptic number.
144153021147511 is a deficient number, since it is larger than the sum of its proper divisors (1).
144153021147511 is an equidigital number, since it uses as much as digits as its factorization.
144153021147511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 40.
Adding to 144153021147511 its reverse (115741120351441), we get a palindrome (259894141498952).
The spelling of 144153021147511 in words is "one hundred forty-four trillion, one hundred fifty-three billion, twenty-one million, one hundred forty-seven thousand, five hundred eleven".
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