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144210040111 is a prime number
BaseRepresentation
bin1000011001001110010…
…1101001010100101111
3111210020020122002001201
42012103211221110233
54330320232240421
6150125453350331
713263442054504
oct2062345512457
9453206562051
10144210040111
1156182898635
1223b477983a7
13107a2b748a7
146da08194ab
153b40635b91
hex219396952f

144210040111 has 2 divisors, whose sum is σ = 144210040112. Its totient is φ = 144210040110.

The previous prime is 144210040097. The next prime is 144210040127. The reversal of 144210040111 is 111040012441.

144210040111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 144210040111 - 213 = 144210031919 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144210040141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72105020055 + 72105020056.

It is an arithmetic number, because the mean of its divisors is an integer number (72105020056).

Almost surely, 2144210040111 is an apocalyptic number.

144210040111 is a deficient number, since it is larger than the sum of its proper divisors (1).

144210040111 is an equidigital number, since it uses as much as digits as its factorization.

144210040111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 144210040111 its reverse (111040012441), we get a palindrome (255250052552).

The spelling of 144210040111 in words is "one hundred forty-four billion, two hundred ten million, forty thousand, one hundred eleven".