Base | Representation |
---|---|
bin | 1000011001001110011… |
… | …0010101001110001001 |
3 | 111210020020222012201001 |
4 | 2012103212111032021 |
5 | 4330320304014123 |
6 | 150125501255001 |
7 | 13263443433634 |
oct | 2062346251611 |
9 | 453206865631 |
10 | 144210219913 |
11 | 56182a00731 |
12 | 23b47864461 |
13 | 107a2c08696 |
14 | 6da0864c1b |
15 | 3b4066e0ad |
hex | 2193995389 |
144210219913 has 2 divisors, whose sum is σ = 144210219914. Its totient is φ = 144210219912.
The previous prime is 144210219911. The next prime is 144210220009. The reversal of 144210219913 is 319912012441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107880716304 + 36329503609 = 328452^2 + 190603^2 .
It is a cyclic number.
It is not a de Polignac number, because 144210219913 - 21 = 144210219911 is a prime.
Together with 144210219911, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (144210219911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72105109956 + 72105109957.
It is an arithmetic number, because the mean of its divisors is an integer number (72105109957).
Almost surely, 2144210219913 is an apocalyptic number.
It is an amenable number.
144210219913 is a deficient number, since it is larger than the sum of its proper divisors (1).
144210219913 is an equidigital number, since it uses as much as digits as its factorization.
144210219913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 144210219913 in words is "one hundred forty-four billion, two hundred ten million, two hundred nineteen thousand, nine hundred thirteen".
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