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144211251443993 is a prime number
BaseRepresentation
bin100000110010100011001100…
…011010100011100100011001
3200220121110110001210111120122
4200302203030122203210121
5122400224120332201433
61230413422340403025
742242630150660006
oct4062431432434431
9626543401714518
10144211251443993
1141a4a714951458
12142111343a6475
1362610a787c666
142787c0cb528ad
1511a13eb5c7198
hex8328cc6a3919

144211251443993 has 2 divisors, whose sum is σ = 144211251443994. Its totient is φ = 144211251443992.

The previous prime is 144211251443971. The next prime is 144211251444017. The reversal of 144211251443993 is 399344152112441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98307482790169 + 45903768653824 = 9915013^2 + 6775232^2 .

It is an emirp because it is prime and its reverse (399344152112441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144211251443993 - 212 = 144211251439897 is a prime.

It is not a weakly prime, because it can be changed into another prime (144211251443953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72105625721996 + 72105625721997.

It is an arithmetic number, because the mean of its divisors is an integer number (72105625721997).

Almost surely, 2144211251443993 is an apocalyptic number.

It is an amenable number.

144211251443993 is a deficient number, since it is larger than the sum of its proper divisors (1).

144211251443993 is an equidigital number, since it uses as much as digits as its factorization.

144211251443993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3732480, while the sum is 53.

The spelling of 144211251443993 in words is "one hundred forty-four trillion, two hundred eleven billion, two hundred fifty-one million, four hundred forty-three thousand, nine hundred ninety-three".