144212114131 has 2 divisors, whose sum is σ = 144212114132. Its totient is φ = 144212114130.

The previous prime is 144212114099. The next prime is 144212114143. The reversal of 144212114131 is 131411212441.

It is a strong prime.

It is an emirp because it is prime and its reverse (131411212441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144212114131 - 2⁵ = 144212114099 is a prime.

It is a super-2 number, since 2×144212114131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144212114096 and 144212114105.

It is not a weakly prime, because it can be changed into another prime (144212124131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72106057065 + 72106057066.

It is an arithmetic number, because the mean of its divisors is an integer number (72106057066).

Almost surely, 2^144212114131 is an apocalyptic number.

144212114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

144212114131 is an equidigital number, since it uses as much as digits as its factorization.

144212114131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 768, while the sum is 25.

Adding to 144212114131 its reverse (131411212441), we get a palindrome (275623326572).

The spelling of 144212114131 in words is "one hundred forty-four billion, two hundred twelve million, one hundred fourteen thousand, one hundred thirty-one".