Base | Representation |
---|---|
bin | 1101000111011011100010… |
… | …0001111010111000011011 |
3 | 1220001122220021021221121021 |
4 | 3101312320201322320123 |
5 | 3342234311041043342 |
6 | 50401015420023311 |
7 | 3015622166620663 |
oct | 321667041727033 |
9 | 56048807257537 |
10 | 14421301112347 |
11 | 4660048573a68 |
12 | 174ab40691b37 |
13 | 807bcc6a427c |
14 | 37bdcd6471a3 |
15 | 1a01e78c2567 |
hex | d1db887ae1b |
14421301112347 has 2 divisors, whose sum is σ = 14421301112348. Its totient is φ = 14421301112346.
The previous prime is 14421301112243. The next prime is 14421301112353. The reversal of 14421301112347 is 74321110312441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14421301112347 - 239 = 13871545298459 is a prime.
It is not a weakly prime, because it can be changed into another prime (14421371112347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210650556173 + 7210650556174.
It is an arithmetic number, because the mean of its divisors is an integer number (7210650556174).
Almost surely, 214421301112347 is an apocalyptic number.
14421301112347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14421301112347 is an equidigital number, since it uses as much as digits as its factorization.
14421301112347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 14421301112347 its reverse (74321110312441), we get a palindrome (88742411424788).
The spelling of 14421301112347 in words is "fourteen trillion, four hundred twenty-one billion, three hundred one million, one hundred twelve thousand, three hundred forty-seven".
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