Base | Representation |
---|---|
bin | 1101000111011011101111… |
… | …0001100011111010100111 |
3 | 1220001200001001201101002222 |
4 | 3101312323301203322213 |
5 | 3342234414004403411 |
6 | 50401025042422555 |
7 | 3015623430364346 |
oct | 321667361437247 |
9 | 56050031641088 |
10 | 14421355544231 |
11 | 4660076271499 |
12 | 174ab56961a5b |
13 | 807c0aa5199c |
14 | 37bdd6975b5d |
15 | 1a01ec5754db |
hex | d1dbbc63ea7 |
14421355544231 has 2 divisors, whose sum is σ = 14421355544232. Its totient is φ = 14421355544230.
The previous prime is 14421355544213. The next prime is 14421355544243. The reversal of 14421355544231 is 13244555312441.
Together with previous prime (14421355544213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14421355544231 is a prime.
It is a super-2 number, since 2×144213555442312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14421355544291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210677772115 + 7210677772116.
It is an arithmetic number, because the mean of its divisors is an integer number (7210677772116).
Almost surely, 214421355544231 is an apocalyptic number.
14421355544231 is a deficient number, since it is larger than the sum of its proper divisors (1).
14421355544231 is an equidigital number, since it uses as much as digits as its factorization.
14421355544231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152000, while the sum is 44.
The spelling of 14421355544231 in words is "fourteen trillion, four hundred twenty-one billion, three hundred fifty-five million, five hundred forty-four thousand, two hundred thirty-one".
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