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1442232322471 is a prime number
BaseRepresentation
bin10100111111001011101…
…111101100100110100111
312002212122122120001201101
4110333023233230212213
5142112142433304341
63022315151540531
7206124601320433
oct24771357544647
95085578501641
101442232322471
11506713602236
121b362082a747
13a60042c6bb5
144db394699c3
15277b0aea831
hex14fcbbec9a7

1442232322471 has 2 divisors, whose sum is σ = 1442232322472. Its totient is φ = 1442232322470.

The previous prime is 1442232322417. The next prime is 1442232322493. The reversal of 1442232322471 is 1742232322441.

Together with previous prime (1442232322417) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1442232322471 - 225 = 1442198768039 is a prime.

It is a super-3 number, since 3×14422323224713 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1442232322471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1442238322471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721116161235 + 721116161236.

It is an arithmetic number, because the mean of its divisors is an integer number (721116161236).

Almost surely, 21442232322471 is an apocalyptic number.

1442232322471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1442232322471 is an equidigital number, since it uses as much as digits as its factorization.

1442232322471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129024, while the sum is 37.

The spelling of 1442232322471 in words is "one trillion, four hundred forty-two billion, two hundred thirty-two million, three hundred twenty-two thousand, four hundred seventy-one".