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14423224041253 is a prime number
BaseRepresentation
bin1101000111100010101100…
…1001010011111100100101
31220001211212021121212011101
43101320223021103330211
53342302230323310003
650401534311040101
73016020636345466
oct321705311237445
956054767555141
1014423224041253
114660944a5aa05
12174b398670031
13808147ba5421
1437c132b9cd6d
151a02ab60e11d
hexd1e2b253f25

14423224041253 has 2 divisors, whose sum is σ = 14423224041254. Its totient is φ = 14423224041252.

The previous prime is 14423224041227. The next prime is 14423224041271. The reversal of 14423224041253 is 35214042232441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7362501572449 + 7060722468804 = 2713393^2 + 2657202^2 .

It is a cyclic number.

It is not a de Polignac number, because 14423224041253 - 25 = 14423224041221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14423224045253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7211612020626 + 7211612020627.

It is an arithmetic number, because the mean of its divisors is an integer number (7211612020627).

Almost surely, 214423224041253 is an apocalyptic number.

It is an amenable number.

14423224041253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14423224041253 is an equidigital number, since it uses as much as digits as its factorization.

14423224041253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 184320, while the sum is 37.

Adding to 14423224041253 its reverse (35214042232441), we get a palindrome (49637266273694).

The spelling of 14423224041253 in words is "fourteen trillion, four hundred twenty-three billion, two hundred twenty-four million, forty-one thousand, two hundred fifty-three".