Base | Representation |
---|---|
bin | 100000110010111111000000… |
… | …101111100101100000101011 |
3 | 200220201022112200111202101021 |
4 | 200302333000233211200223 |
5 | 122401221303310321301 |
6 | 1230435242252033311 |
7 | 42245035266633433 |
oct | 4062770057454053 |
9 | 626638480452337 |
10 | 144241120401451 |
11 | 41a61352121267 |
12 | 14216a8b462837 |
13 | 6263b57a52598 |
14 | 2789443a092c3 |
15 | 11a20989688a1 |
hex | 832fc0be582b |
144241120401451 has 2 divisors, whose sum is σ = 144241120401452. Its totient is φ = 144241120401450.
The previous prime is 144241120401437. The next prime is 144241120401461. The reversal of 144241120401451 is 154104021142441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144241120401451 - 25 = 144241120401419 is a prime.
It is not a weakly prime, because it can be changed into another prime (144241120401421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72120560200725 + 72120560200726.
It is an arithmetic number, because the mean of its divisors is an integer number (72120560200726).
Almost surely, 2144241120401451 is an apocalyptic number.
144241120401451 is a deficient number, since it is larger than the sum of its proper divisors (1).
144241120401451 is an equidigital number, since it uses as much as digits as its factorization.
144241120401451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20480, while the sum is 34.
Adding to 144241120401451 its reverse (154104021142441), we get a palindrome (298345141543892).
The spelling of 144241120401451 in words is "one hundred forty-four trillion, two hundred forty-one billion, one hundred twenty million, four hundred one thousand, four hundred fifty-one".
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