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144244440235223 is a prime number
BaseRepresentation
bin100000110011000010000110…
…100111101111110011010111
3200220201122010001100210011122
4200303002012213233303113
5122401300103200011343
61230440551523354155
742245213461023206
oct4063020647576327
9626648101323148
10144244440235223
1141a627a6082539
121421765722295b
13626426678a473
14278967a8a923d
1511a21e0138068
hex8330869efcd7

144244440235223 has 2 divisors, whose sum is σ = 144244440235224. Its totient is φ = 144244440235222.

The previous prime is 144244440235199. The next prime is 144244440235277. The reversal of 144244440235223 is 322532044442441.

It is a weak prime.

It is an emirp because it is prime and its reverse (322532044442441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144244440235223 - 28 = 144244440234967 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144244440231223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72122220117611 + 72122220117612.

It is an arithmetic number, because the mean of its divisors is an integer number (72122220117612).

Almost surely, 2144244440235223 is an apocalyptic number.

144244440235223 is a deficient number, since it is larger than the sum of its proper divisors (1).

144244440235223 is an equidigital number, since it uses as much as digits as its factorization.

144244440235223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2949120, while the sum is 44.

Adding to 144244440235223 its reverse (322532044442441), we get a palindrome (466776484677664).

The spelling of 144244440235223 in words is "one hundred forty-four trillion, two hundred forty-four billion, four hundred forty million, two hundred thirty-five thousand, two hundred twenty-three".