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144264121000 = 2353120112
BaseRepresentation
bin1000011001011011001…
…1111100101010101000
3111210101000101200002121
42012112303330222220
54330423103333000
6150135104441024
713264666536646
oct2062663745250
9453330350077
10144264121000
115620037638a
1223b61919174
13107b112b60c
146da7a96196
153b45269b1a
hex2196cfcaa8

144264121000 has 48 divisors (see below), whose sum is σ = 337606151220. Its totient is φ = 57700844000.

The previous prime is 144264120953. The next prime is 144264121007. The reversal of 144264121000 is 121462441.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

144264121000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 97522545796 + 46741575204 = 312286^2 + 216198^2 .

It is a super-3 number, since 3×1442641210003 (a number of 34 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (144264121007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12004995 + ... + 12017005.

Almost surely, 2144264121000 is an apocalyptic number.

144264121000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

144264121000 is an abundant number, since it is smaller than the sum of its proper divisors (193342030220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

144264121000 is an frugal number, since it uses more digits than its factorization.

144264121000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24043 (or 12018 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 144264121000 its reverse (121462441), we get a palindrome (144385583441).

It can be divided in two parts, 1442641 and 21000, that added together give a palindrome (1463641).

The spelling of 144264121000 in words is "one hundred forty-four billion, two hundred sixty-four million, one hundred twenty-one thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 12011 24022 48044 60055 96088 120110 240220 300275 480440 600550 1201100 1501375 2402200 3002750 6005500 12011000 144264121 288528242 577056484 721320605 1154112968 1442641210 2885282420 3606603025 5770564840 7213206050 14426412100 18033015125 28852824200 36066030250 72132060500 144264121000