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14427034632401 is a prime number
BaseRepresentation
bin1101000111110000111001…
…0001100100000011010001
31220002012200211220221111212
43101330032101210003101
53342333031331214101
650403404353145505
73016214240005616
oct321741621440321
956065624827455
1014427034632401
11466251aa35496
12175008085b295
138086044aa4a1
1437c3b4cca50d
151a0430e1d1bb
hexd1f0e4640d1

14427034632401 has 2 divisors, whose sum is σ = 14427034632402. Its totient is φ = 14427034632400.

The previous prime is 14427034632317. The next prime is 14427034632403. The reversal of 14427034632401 is 10423643072441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14282927084176 + 144107548225 = 3779276^2 + 379615^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14427034632401 is a prime.

Together with 14427034632403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14427034632403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7213517316200 + 7213517316201.

It is an arithmetic number, because the mean of its divisors is an integer number (7213517316201).

Almost surely, 214427034632401 is an apocalyptic number.

It is an amenable number.

14427034632401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14427034632401 is an equidigital number, since it uses as much as digits as its factorization.

14427034632401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 387072, while the sum is 41.

The spelling of 14427034632401 in words is "fourteen trillion, four hundred twenty-seven billion, thirty-four million, six hundred thirty-two thousand, four hundred one".