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1443004135481 is a prime number
BaseRepresentation
bin10100111111111001101…
…111111011100000111001
312002221122102212020010102
4110333321233323200321
5142120233024313411
63022523522325145
7206152662526226
oct24777157734071
95087572766112
101443004135481
11506a7a240827
121b37b71b97b5
13a60c818b09c
144dbadb7894d
1527808755d3b
hex14ff9bfb839

1443004135481 has 2 divisors, whose sum is σ = 1443004135482. Its totient is φ = 1443004135480.

The previous prime is 1443004135403. The next prime is 1443004135541. The reversal of 1443004135481 is 1845314003441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1381351245481 + 61652890000 = 1175309^2 + 248300^2 .

It is a cyclic number.

It is not a de Polignac number, because 1443004135481 - 210 = 1443004134457 is a prime.

It is a super-2 number, since 2×14430041354812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1443004135081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721502067740 + 721502067741.

It is an arithmetic number, because the mean of its divisors is an integer number (721502067741).

Almost surely, 21443004135481 is an apocalyptic number.

It is an amenable number.

1443004135481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1443004135481 is an equidigital number, since it uses as much as digits as its factorization.

1443004135481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 92160, while the sum is 38.

The spelling of 1443004135481 in words is "one trillion, four hundred forty-three billion, four million, one hundred thirty-five thousand, four hundred eighty-one".