Base | Representation |
---|---|
bin | 100000110011111111011000… |
… | …001001000011111100011011 |
3 | 200220221220221012222200201122 |
4 | 200303333120021003330123 |
5 | 122403334324000314121 |
6 | 1230531112222435455 |
7 | 42253033042333163 |
oct | 4063773011037433 |
9 | 626856835880648 |
10 | 144310232432411 |
11 | 41a88698059021 |
12 | 14228358a32b8b |
13 | 626a520226666 |
14 | 278c91c7175a3 |
15 | 11a3c911275ab |
hex | 833fd8243f1b |
144310232432411 has 2 divisors, whose sum is σ = 144310232432412. Its totient is φ = 144310232432410.
The previous prime is 144310232432407. The next prime is 144310232432413. The reversal of 144310232432411 is 114234232013441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144310232432411 - 22 = 144310232432407 is a prime.
Together with 144310232432413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (144310232432413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72155116216205 + 72155116216206.
It is an arithmetic number, because the mean of its divisors is an integer number (72155116216206).
Almost surely, 2144310232432411 is an apocalyptic number.
144310232432411 is a deficient number, since it is larger than the sum of its proper divisors (1).
144310232432411 is an equidigital number, since it uses as much as digits as its factorization.
144310232432411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 144310232432411 its reverse (114234232013441), we get a palindrome (258544464445852).
The spelling of 144310232432411 in words is "one hundred forty-four trillion, three hundred ten billion, two hundred thirty-two million, four hundred thirty-two thousand, four hundred eleven".
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