Base | Representation |
---|---|
bin | 1101001000000000000010… |
… | …1010101110010000111111 |
3 | 1220002121012021002210001222 |
4 | 3102000000222232100333 |
5 | 3342414343414022421 |
6 | 50405320104223555 |
7 | 3016420100145536 |
oct | 322000052562077 |
9 | 56077167083058 |
10 | 14431101314111 |
11 | 4664217523669 |
12 | 1750a1676abbb |
13 | 808b01b78221 |
14 | 37c67d03b31d |
15 | 1a05bce65cab |
hex | d2000aae43f |
14431101314111 has 2 divisors, whose sum is σ = 14431101314112. Its totient is φ = 14431101314110.
The previous prime is 14431101314059. The next prime is 14431101314293. The reversal of 14431101314111 is 11141310113441.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14431101314111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14431101311111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7215550657055 + 7215550657056.
It is an arithmetic number, because the mean of its divisors is an integer number (7215550657056).
Almost surely, 214431101314111 is an apocalyptic number.
14431101314111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14431101314111 is an equidigital number, since it uses as much as digits as its factorization.
14431101314111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 26.
Adding to 14431101314111 its reverse (11141310113441), we get a palindrome (25572411427552).
The spelling of 14431101314111 in words is "fourteen trillion, four hundred thirty-one billion, one hundred one million, three hundred fourteen thousand, one hundred eleven".
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