Base | Representation |
---|---|
bin | 100000110100001010010010… |
… | …000010001111000011110111 |
3 | 200221000001011012222122121021 |
4 | 200310022102002033003313 |
5 | 122404032313412432303 |
6 | 1230540330125002011 |
7 | 42253626145604065 |
oct | 4064122202170367 |
9 | 627001135878537 |
10 | 144321941139703 |
11 | 41a92656343118 |
12 | 1422a6860b3307 |
13 | 626b667c1b722 |
14 | 278d30d78b035 |
15 | 11a4229008ebd |
hex | 83429208f0f7 |
144321941139703 has 2 divisors, whose sum is σ = 144321941139704. Its totient is φ = 144321941139702.
The previous prime is 144321941139697. The next prime is 144321941139713. The reversal of 144321941139703 is 307931149123441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144321941139703 - 221 = 144321939042551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144321941139713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72160970569851 + 72160970569852.
It is an arithmetic number, because the mean of its divisors is an integer number (72160970569852).
Almost surely, 2144321941139703 is an apocalyptic number.
144321941139703 is a deficient number, since it is larger than the sum of its proper divisors (1).
144321941139703 is an equidigital number, since it uses as much as digits as its factorization.
144321941139703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 52.
The spelling of 144321941139703 in words is "one hundred forty-four trillion, three hundred twenty-one billion, nine hundred forty-one million, one hundred thirty-nine thousand, seven hundred three".
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