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14433121133 is a prime number
BaseRepresentation
bin11010111000100011…
…11111001101101101
31101020212110112001222
431130101333031231
5214024334334013
610344103513125
71020444335234
oct153421771555
941225415058
1014433121133
116137136592
1229697587a5
131490278c82
149acc1db1b
1559718a508
hex35c47f36d

14433121133 has 2 divisors, whose sum is σ = 14433121134. Its totient is φ = 14433121132.

The previous prime is 14433121117. The next prime is 14433121139. The reversal of 14433121133 is 33112133441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14184333604 + 248787529 = 119098^2 + 15773^2 .

It is an emirp because it is prime and its reverse (33112133441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14433121133 - 24 = 14433121117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14433121139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216560566 + 7216560567.

It is an arithmetic number, because the mean of its divisors is an integer number (7216560567).

Almost surely, 214433121133 is an apocalyptic number.

It is an amenable number.

14433121133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433121133 is an equidigital number, since it uses as much as digits as its factorization.

14433121133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 26.

Adding to 14433121133 its reverse (33112133441), we get a palindrome (47545254574).

The spelling of 14433121133 in words is "fourteen billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-three".