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14433212140153 is a prime number
BaseRepresentation
bin1101001000000111111001…
…1110111000101001111001
31220002210122100222212001021
43102001332132320221321
53342433204301441103
650410305350422441
73016523310652402
oct322017636705171
956083570885037
1014433212140153
1146650aaa864a4
121751305661a21
1380907a286911
1437c7dd5049a9
151a069341abbd
hexd207e7b8a79

14433212140153 has 2 divisors, whose sum is σ = 14433212140154. Its totient is φ = 14433212140152.

The previous prime is 14433212140091. The next prime is 14433212140157. The reversal of 14433212140153 is 35104121233441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8689271331049 + 5743940809104 = 2947757^2 + 2396652^2 .

It is a cyclic number.

It is not a de Polignac number, because 14433212140153 - 29 = 14433212139641 is a prime.

It is a super-2 number, since 2×144332121401532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14433212140157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216606070076 + 7216606070077.

It is an arithmetic number, because the mean of its divisors is an integer number (7216606070077).

Almost surely, 214433212140153 is an apocalyptic number.

It is an amenable number.

14433212140153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433212140153 is an equidigital number, since it uses as much as digits as its factorization.

14433212140153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 14433212140153 its reverse (35104121233441), we get a palindrome (49537333373594).

The spelling of 14433212140153 in words is "fourteen trillion, four hundred thirty-three billion, two hundred twelve million, one hundred forty thousand, one hundred fifty-three".