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14433443220181 is a prime number
BaseRepresentation
bin1101001000001000110001…
…0000011000101011010101
31220002211020110210221020211
43102002030100120223111
53342434142431021211
650410344323325421
73016532115054166
oct322021420305325
956084213727224
1014433443220181
114665209467327
12175136ab20871
138090b610366b
1437c82209776d
151a06a8863e21
hexd208c418ad5

14433443220181 has 2 divisors, whose sum is σ = 14433443220182. Its totient is φ = 14433443220180.

The previous prime is 14433443220169. The next prime is 14433443220199. The reversal of 14433443220181 is 18102234433441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10961668127281 + 3471775092900 = 3310841^2 + 1863270^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14433443220181 is a prime.

It is a super-2 number, since 2×144334432201812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14433443220881) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216721610090 + 7216721610091.

It is an arithmetic number, because the mean of its divisors is an integer number (7216721610091).

Almost surely, 214433443220181 is an apocalyptic number.

It is an amenable number.

14433443220181 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433443220181 is an equidigital number, since it uses as much as digits as its factorization.

14433443220181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 40.

The spelling of 14433443220181 in words is "fourteen trillion, four hundred thirty-three billion, four hundred forty-three million, two hundred twenty thousand, one hundred eighty-one".