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14434204440251 is a prime number
BaseRepresentation
bin1101001000001011100110…
…1000001101011010111011
31220002220012112011220212202
43102002321220031122323
53342442222314042001
650410552035100415
73016560020243531
oct322027150153273
956086175156782
1014434204440251
11466556a120222
121751541a4170b
138091a7a2913b
1437c89520a151
151a07005ca96b
hexd20b9a0d6bb

14434204440251 has 2 divisors, whose sum is σ = 14434204440252. Its totient is φ = 14434204440250.

The previous prime is 14434204440163. The next prime is 14434204440283. The reversal of 14434204440251 is 15204440243441.

14434204440251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14434204440251 is a prime.

It is a super-3 number, since 3×144342044402513 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (14434204440151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217102220125 + 7217102220126.

It is an arithmetic number, because the mean of its divisors is an integer number (7217102220126).

Almost surely, 214434204440251 is an apocalyptic number.

14434204440251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434204440251 is an equidigital number, since it uses as much as digits as its factorization.

14434204440251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 245760, while the sum is 38.

Adding to 14434204440251 its reverse (15204440243441), we get a palindrome (29638644683692).

The spelling of 14434204440251 in words is "fourteen trillion, four hundred thirty-four billion, two hundred four million, four hundred forty thousand, two hundred fifty-one".